Quote:
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Originally Posted by the_fat_man
I need to recode my program using this algorithm.
Presently using the 6 Ls per second. Not that I pay attention much attention to this. Does it matter?
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now this is really odd -
If I use the traditional method of .2 (or .167) whatever seconds per length and then subtract that from the splits , I get the same answer as the original post (24.21 , 24.43).
- *see work shown below
However if I calculate it by feet per second (velocity) my answer is different.
All im doing with the velocity is saying that street sense ran more feet in the same amount of seconds(faster). The more feet comes from the 3.5 beaten lengths * 8feet in a beaten length(some use 9,10) Then I just went back and divided the total feet in 2 furlongs by the ft/s velocity.
Either I am doing something wrong with my math or their is a funky difference between the methods.
work for traditional math
*last 4 furlongs -
6f--->wire
.2 seconds *12 = 2.4
48.64
24.21
last 2 furlongs
1m ---> wire
.2seconds * 3.5 = .7
25.13 - .7 =
24.43